漸化式 演習6

a₁ = 1 , a_n+1 = 3a_n + 2ⁿ

a₁ = 2 , ( a_n+1 )² = 4(a_n)³

a₁ = 1 , na_n+1 = (n+1)a_n +1

a₁ = 2 , 3na_n+1 = (n+1)a_n

a₁ = 1 , (n+3)a_n+1 = na_n

a₁ = 1/2 , a_n+1 = a_n / ( 2- a_n )

a₁ = 8 , a_n+1 = ( 3a_n +2 ) / ( a_n +2 )

(ハイレベル)

a₁ = 1 , a₂ =2 , a_n+2 - 2a_n+1 -15a_n =0

a₁ = 3 , a₂ =5 , a_n+2 - 3a_n+1 +2a_n =0

4-1

5-1

7-1

7-2

7-3