Σの計算 演習10
nΣk=1 ( 2k2 +5k-3 )
nΣk=1 (-1/3)k
nΣk=1 ( 2k -1 )
nΣk=1 k( n-k )
nΣk=1 (1/3)( 10k -1 )
nΣk=1 (5/9){ 1-(1/10)k }
4 + n-1Σk=1 ( k2 +1 )
nΣk=1 ( 2k2 +5k-3 )
nΣk=1 (-1/3)k
nΣk=1 ( 2k -1 )
nΣk=1 k( n-k )
nΣk=1 (1/3)( 10k -1 )
nΣk=1 (5/9){ 1-(1/10)k }
4 + n-1Σk=1 ( k2 +1 )