Σの計算 演習13
nΣk=1 ( 2k+1 )3
1/3 + 1/3 n-1Σk=1 (-1/3)k
nΣk=1 (3k2 +4k )
nΣk=1 { 4k3 + (n+1)k }
nΣk=1 ( k2 +1 )( 4k+3 )
nΣk=1 ( 2k+1 )3
1/3 + 1/3 n-1Σk=1 (-1/3)k
nΣk=1 (3k2 +4k )
nΣk=1 { 4k3 + (n+1)k }
nΣk=1 ( k2 +1 )( 4k+3 )